To understand this graph, we can handle the details one at a time First of all, secant is the reciprocal of cosine This means that if we can graph {eq}y=12\cos\left2\left(x\dfrac{\pi}{2}\right Please Subscribe here, thank you!!! The #x^2# is positive so the general graph shape is #uu# Consider the generalised form of #y=ax^2bxc# The #bx# part of the equation shifts the graph left or right You do not have any #bx# type of value in your equation So the graph is central about the yaxis The #c# part of the equation is of value 1 so it lifts the vertex up from y=0
Instructional Unit The Parabola Day 4 And 5
